Base | Representation |
---|---|
bin | 111110000111101001… |
… | …0101110111001101010 |
3 | 110202022220200100021112 |
4 | 1330033102232321222 |
5 | 4141201020230424 |
6 | 141141112510322 |
7 | 12431535003131 |
oct | 1741722567152 |
9 | 422286610245 |
10 | 133400555114 |
11 | 51636154562 |
12 | 21a2b6ab3a2 |
13 | c76c563218 |
14 | 6656d7c918 |
15 | 370b67a60e |
hex | 1f0f4aee6a |
133400555114 has 4 divisors (see below), whose sum is σ = 200100832674. Its totient is φ = 66700277556.
The previous prime is 133400555083. The next prime is 133400555149. The reversal of 133400555114 is 411555004331.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 411555004331 = 677 ⋅607909903.
It can be written as a sum of positive squares in only one way, i.e., 73152398089 + 60248157025 = 270467^2 + 245455^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33350138777 + ... + 33350138780.
Almost surely, 2133400555114 is an apocalyptic number.
133400555114 is a deficient number, since it is larger than the sum of its proper divisors (66700277560).
133400555114 is an equidigital number, since it uses as much as digits as its factorization.
133400555114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66700277559.
The product of its (nonzero) digits is 18000, while the sum is 32.
Adding to 133400555114 its reverse (411555004331), we get a palindrome (544955559445).
The spelling of 133400555114 in words is "one hundred thirty-three billion, four hundred million, five hundred fifty-five thousand, one hundred fourteen".
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