Search a number
-
+
133401223432457 is a prime number
BaseRepresentation
bin11110010101001111100100…
…100010010000100100001001
3122111100000212121221202000222
4132111033210202100210021
5114441121201144314312
61151415402004035425
740045630450651211
oct3625174442204411
9574300777852028
10133401223432457
1139562160957202
1212b66073992b75
1359588b2030446
1424d2921927241
151065112cee672
hex7953e4890909

133401223432457 has 2 divisors, whose sum is σ = 133401223432458. Its totient is φ = 133401223432456.

The previous prime is 133401223432447. The next prime is 133401223432507. The reversal of 133401223432457 is 754234322104331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 76180410403321 + 57220813029136 = 8728139^2 + 7564444^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133401223432457 is a prime.

It is not a weakly prime, because it can be changed into another prime (133401223432447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66700611716228 + 66700611716229.

It is an arithmetic number, because the mean of its divisors is an integer number (66700611716229).

Almost surely, 2133401223432457 is an apocalyptic number.

It is an amenable number.

133401223432457 is a deficient number, since it is larger than the sum of its proper divisors (1).

133401223432457 is an equidigital number, since it uses as much as digits as its factorization.

133401223432457 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1451520, while the sum is 44.

Adding to 133401223432457 its reverse (754234322104331), we get a palindrome (887635545536788).

The spelling of 133401223432457 in words is "one hundred thirty-three trillion, four hundred one billion, two hundred twenty-three million, four hundred thirty-two thousand, four hundred fifty-seven".