133401253135 has 4 divisors (see below), whose sum is σ = 160081503768. Its totient is φ = 106721002504.

The previous prime is 133401253127. The next prime is 133401253157. The reversal of 133401253135 is 531352104331.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 531352104331 = 173 ⋅3071399447.

It is a cyclic number.

It is not a de Polignac number, because 133401253135 - 2³ = 133401253127 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133401253097 and 133401253106.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13340125309 + ... + 13340125318.

It is an arithmetic number, because the mean of its divisors is an integer number (40020375942).

Almost surely, 2^133401253135 is an apocalyptic number.

133401253135 is a deficient number, since it is larger than the sum of its proper divisors (26680250633).

133401253135 is an equidigital number, since it uses as much as digits as its factorization.

133401253135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26680250632.

The product of its (nonzero) digits is 16200, while the sum is 31.

Adding to 133401253135 its reverse (531352104331), we get a palindrome (664753357466).

The spelling of 133401253135 in words is "one hundred thirty-three billion, four hundred one million, two hundred fifty-three thousand, one hundred thirty-five".