Base | Representation |
---|---|
bin | 11110010101010000000110… |
… | …011101101110101011010001 |
3 | 122111100002100022002000201101 |
4 | 132111100012131232223101 |
5 | 114441123332410423132 |
6 | 1151415534300504401 |
7 | 40045650532256125 |
oct | 3625200635565321 |
9 | 574302308060641 |
10 | 133401792670417 |
11 | 395624232040a7 |
12 | 12b661b254b101 |
13 | 5958972c4823b |
14 | 24d2977383585 |
15 | 1065147c927e7 |
hex | 79540676ead1 |
133401792670417 has 2 divisors, whose sum is σ = 133401792670418. Its totient is φ = 133401792670416.
The previous prime is 133401792670387. The next prime is 133401792670499. The reversal of 133401792670417 is 714076297104331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 133189349111361 + 212443559056 = 11540769^2 + 460916^2 .
It is a cyclic number.
It is not a de Polignac number, because 133401792670417 - 223 = 133401784281809 is a prime.
It is not a weakly prime, because it can be changed into another prime (133401792673417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66700896335208 + 66700896335209.
It is an arithmetic number, because the mean of its divisors is an integer number (66700896335209).
Almost surely, 2133401792670417 is an apocalyptic number.
It is an amenable number.
133401792670417 is a deficient number, since it is larger than the sum of its proper divisors (1).
133401792670417 is an equidigital number, since it uses as much as digits as its factorization.
133401792670417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5334336, while the sum is 55.
The spelling of 133401792670417 in words is "one hundred thirty-three trillion, four hundred one billion, seven hundred ninety-two million, six hundred seventy thousand, four hundred seventeen".
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