Base | Representation |
---|---|
bin | 11000110110010010… |
… | …10010101010010111 |
3 | 1021102201011121002212 |
4 | 30123021102222113 |
5 | 204310110304310 |
6 | 10043425224035 |
7 | 651404604245 |
oct | 143311225227 |
9 | 37381147085 |
10 | 13340322455 |
11 | 572629a789 |
12 | 270379201b |
13 | 1347a4a035 |
14 | 907a37795 |
15 | 531278205 |
hex | 31b252a97 |
13340322455 has 4 divisors (see below), whose sum is σ = 16008386952. Its totient is φ = 10672257960.
The previous prime is 13340322431. The next prime is 13340322461. The reversal of 13340322455 is 55422304331.
13340322455 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13340322455 - 210 = 13340321431 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1334032241 + ... + 1334032250.
It is an arithmetic number, because the mean of its divisors is an integer number (4002096738).
Almost surely, 213340322455 is an apocalyptic number.
13340322455 is a deficient number, since it is larger than the sum of its proper divisors (2668064497).
13340322455 is an equidigital number, since it uses as much as digits as its factorization.
13340322455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2668064496.
The product of its (nonzero) digits is 43200, while the sum is 32.
Adding to 13340322455 its reverse (55422304331), we get a palindrome (68762626786).
The spelling of 13340322455 in words is "thirteen billion, three hundred forty million, three hundred twenty-two thousand, four hundred fifty-five".
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