Base | Representation |
---|---|
bin | 111110000111101111… |
… | …1111011001001100010 |
3 | 110202100011012000211002 |
4 | 1330033133323021202 |
5 | 4141202411410104 |
6 | 141141314552002 |
7 | 12431606254646 |
oct | 1741737731142 |
9 | 422304160732 |
10 | 133404013154 |
11 | 516380a6645 |
12 | 21a30898602 |
13 | c7701a41b9 |
14 | 66575dcc26 |
15 | 370bb1001e |
hex | 1f0f7fb262 |
133404013154 has 4 divisors (see below), whose sum is σ = 200106019734. Its totient is φ = 66702006576.
The previous prime is 133404013151. The next prime is 133404013163. The reversal of 133404013154 is 451310404331.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 451310404331 = 17 ⋅26547670843.
It can be written as a sum of positive squares in only one way, i.e., 133314805129 + 89208025 = 365123^2 + 9445^2 .
It is not an unprimeable number, because it can be changed into a prime (133404013151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33351003287 + ... + 33351003290.
Almost surely, 2133404013154 is an apocalyptic number.
133404013154 is a deficient number, since it is larger than the sum of its proper divisors (66702006580).
133404013154 is an equidigital number, since it uses as much as digits as its factorization.
133404013154 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66702006579.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 133404013154 its reverse (451310404331), we get a palindrome (584714417485).
The spelling of 133404013154 in words is "one hundred thirty-three billion, four hundred four million, thirteen thousand, one hundred fifty-four".
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