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1334041044143 = 12809104148727
BaseRepresentation
bin10011011010011011000…
…010101110010010101111
311201112101121120200000212
4103122123002232102233
5133324104001403033
62500503333213035
7165244531531133
oct23323302562257
94645347520025
101334041044143
11474844433525
1219666779117b
1398a51751b02
14487d458d3c3
1524a7c6d0748
hex1369b0ae4af

1334041044143 has 4 divisors (see below), whose sum is σ = 1334145205680. Its totient is φ = 1333936882608.

The previous prime is 1334041044113. The next prime is 1334041044157. The reversal of 1334041044143 is 3414401404331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1334041044143 - 26 = 1334041044079 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1334041044113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52061555 + ... + 52087172.

It is an arithmetic number, because the mean of its divisors is an integer number (333536301420).

Almost surely, 21334041044143 is an apocalyptic number.

1334041044143 is a deficient number, since it is larger than the sum of its proper divisors (104161537).

1334041044143 is a wasteful number, since it uses less digits than its factorization.

1334041044143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 104161536.

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 1334041044143 its reverse (3414401404331), we get a palindrome (4748442448474).

The spelling of 1334041044143 in words is "one trillion, three hundred thirty-four billion, forty-one million, forty-four thousand, one hundred forty-three".

Divisors: 1 12809 104148727 1334041044143