13340411111131 has 32 divisors (see below), whose sum is σ = 15138378178560. Its totient is φ = 11663233300224.

The previous prime is 13340411111033. The next prime is 13340411111141. The reversal of 13340411111131 is 13111111404331.

13340411111131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 13340411111131 - 2¹⁷ = 13340410980059 is a prime.

It is a super-2 number, since 2×13340411111131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13340411111096 and 13340411111105.

It is not an unprimeable number, because it can be changed into a prime (13340411111141) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 410723350 + ... + 410755828.

It is an arithmetic number, because the mean of its divisors is an integer number (473074318080).

Almost surely, 2^{13340411111131} is an apocalyptic number.

13340411111131 is a deficient number, since it is larger than the sum of its proper divisors (1797967067429).

13340411111131 is a wasteful number, since it uses less digits than its factorization.

13340411111131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45955.

The product of its (nonzero) digits is 432, while the sum is 25.

Adding to 13340411111131 its reverse (13111111404331), we get a palindrome (26451522515462).

The spelling of 13340411111131 in words is "thirteen trillion, three hundred forty billion, four hundred eleven million, one hundred eleven thousand, one hundred thirty-one".