Base | Representation |
---|---|
bin | 1100001000100001000000… |
… | …1100011010111110001010 |
3 | 1202020100000012122011002211 |
4 | 3002020100030122332022 |
5 | 3222032210132104114 |
6 | 44212302533415334 |
7 | 2544546353665156 |
oct | 302102014327612 |
9 | 52210005564084 |
10 | 13340440113034 |
11 | 4283715728511 |
12 | 15b557249a54a |
13 | 759cc8ab3c98 |
14 | 341975d7c066 |
15 | 1820372b66c4 |
hex | c221031af8a |
13340440113034 has 8 divisors (see below), whose sum is σ = 20010690974340. Its totient is φ = 6670209788256.
The previous prime is 13340440112941. The next prime is 13340440113053. The reversal of 13340440113034 is 43031104404331.
It is a happy number.
It can be written as a sum of positive squares in 2 ways, for example, as 11237948813025 + 2102491300009 = 3352305^2 + 1449997^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 13340440112987 and 13340440113005.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3391899 + ... + 6179470.
Almost surely, 213340440113034 is an apocalyptic number.
13340440113034 is a deficient number, since it is larger than the sum of its proper divisors (6670250861306).
13340440113034 is an equidigital number, since it uses as much as digits as its factorization.
13340440113034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10268264.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 13340440113034 its reverse (43031104404331), we get a palindrome (56371544517365).
The spelling of 13340440113034 in words is "thirteen trillion, three hundred forty billion, four hundred forty million, one hundred thirteen thousand, thirty-four".
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