Base | Representation |
---|---|
bin | 111110000111110010… |
… | …1100010101111100011 |
3 | 110202100020221212020211 |
4 | 1330033211202233203 |
5 | 4141203301023201 |
6 | 141141410314551 |
7 | 12431624631055 |
oct | 1741745425743 |
9 | 422306855224 |
10 | 133405486051 |
11 | 51638a12212 |
12 | 21a31288a57 |
13 | c77059b736 |
14 | 66578a38d5 |
15 | 370bd01651 |
hex | 1f0f962be3 |
133405486051 has 2 divisors, whose sum is σ = 133405486052. Its totient is φ = 133405486050.
The previous prime is 133405486043. The next prime is 133405486141. The reversal of 133405486051 is 150684504331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 133405486051 - 23 = 133405486043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133405485995 and 133405486013.
It is not a weakly prime, because it can be changed into another prime (133402486051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66702743025 + 66702743026.
It is an arithmetic number, because the mean of its divisors is an integer number (66702743026).
Almost surely, 2133405486051 is an apocalyptic number.
133405486051 is a deficient number, since it is larger than the sum of its proper divisors (1).
133405486051 is an equidigital number, since it uses as much as digits as its factorization.
133405486051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 172800, while the sum is 40.
The spelling of 133405486051 in words is "one hundred thirty-three billion, four hundred five million, four hundred eighty-six thousand, fifty-one".
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