133410011443044 has 72 divisors (see below), whose sum is σ = 363138704314848. Its totient is φ = 38009165483520.

The previous prime is 133410011443003. The next prime is 133410011443069. The reversal of 133410011443044 is 440344110014331.

133410011443044 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 133410011442996 and 133410011443014.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 321163222 + ... + 321578349.

It is an arithmetic number, because the mean of its divisors is an integer number (5043593115484).

Almost surely, 2^{133410011443044} is an apocalyptic number.

133410011443044 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

It is an amenable number.

133410011443044 is an abundant number, since it is smaller than the sum of its proper divisors (229728692871804).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133410011443044 is a wasteful number, since it uses less digits than its factorization.

133410011443044 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 642741945 (or 642741936 counting only the distinct ones).

The product of its (nonzero) digits is 27648, while the sum is 33.

Adding to 133410011443044 its reverse (440344110014331), we get a palindrome (573754121457375).

The spelling of 133410011443044 in words is "one hundred thirty-three trillion, four hundred ten billion, eleven million, four hundred forty-three thousand, forty-four".