Base | Representation |
---|---|
bin | 111110000111111101… |
… | …0101111011011000011 |
3 | 110202100122102011222011 |
4 | 1330033322233123003 |
5 | 4141211211334021 |
6 | 141142125353351 |
7 | 12432023104111 |
oct | 1741772573303 |
9 | 422318364864 |
10 | 133411043011 |
11 | 51641068244 |
12 | 21a33108857 |
13 | c771795b8c |
14 | 665850cab1 |
15 | 370c54cde1 |
hex | 1f0feaf6c3 |
133411043011 has 2 divisors, whose sum is σ = 133411043012. Its totient is φ = 133411043010.
The previous prime is 133411042951. The next prime is 133411043027. The reversal of 133411043011 is 110340114331.
It is a strong prime.
It is an emirp because it is prime and its reverse (110340114331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133411043011 - 231 = 131263559363 is a prime.
It is a super-2 number, since 2×1334110430112 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (133411043911) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66705521505 + 66705521506.
It is an arithmetic number, because the mean of its divisors is an integer number (66705521506).
Almost surely, 2133411043011 is an apocalyptic number.
133411043011 is a deficient number, since it is larger than the sum of its proper divisors (1).
133411043011 is an equidigital number, since it uses as much as digits as its factorization.
133411043011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 133411043011 its reverse (110340114331), we get a palindrome (243751157342).
The spelling of 133411043011 in words is "one hundred thirty-three billion, four hundred eleven million, forty-three thousand, eleven".
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