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133411103233 = 712113889271
BaseRepresentation
bin111110000111111101…
…0111110001000000001
3110202100122112020120121
41330033322332020001
54141211220300413
6141142130540241
712432023444512
oct1741772761001
9422318466517
10133411103233
11516410a9511
1221a33137681
13c7717b7405
146658526a09
15370c560b8d
hex1f0febe201

133411103233 has 8 divisors (see below), whose sum is σ = 135354312576. Its totient is φ = 131469676800.

The previous prime is 133411103191. The next prime is 133411103251. The reversal of 133411103233 is 332301114331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 133411103233 - 217 = 133410972161 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133411103198 and 133411103207.

It is not an unprimeable number, because it can be changed into a prime (133411103933) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 294613 + ... + 594658.

It is an arithmetic number, because the mean of its divisors is an integer number (16919289072).

Almost surely, 2133411103233 is an apocalyptic number.

It is an amenable number.

133411103233 is a deficient number, since it is larger than the sum of its proper divisors (1943209343).

133411103233 is an equidigital number, since it uses as much as digits as its factorization.

133411103233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 891455.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 133411103233 its reverse (332301114331), we get a palindrome (465712217564).

The spelling of 133411103233 in words is "one hundred thirty-three billion, four hundred eleven million, one hundred three thousand, two hundred thirty-three".

Divisors: 1 71 2113 150023 889271 63138241 1879029623 133411103233