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13341124521120 = 25351119314289861
BaseRepresentation
bin1100001000100011100011…
…1111001110110010100000
31202020101202220110200111110
43002020320333032302200
53222040110334133440
644212454502543320
72544602334240054
oct302107077166240
952211686420443
1013341124521120
114283a36a98430
1215b5723737b40
1375a0a7824496
143419dcc17c64
15182077409080
hexc2238fceca0

13341124521120 has 384 divisors, whose sum is σ = 49814563921920. Its totient is φ = 2965151232000.

The previous prime is 13341124521119. The next prime is 13341124521121. The reversal of 13341124521120 is 2112542114331.

It is an interprime number because it is at equal distance from previous prime (13341124521119) and next prime (13341124521121).

It is a Harshad number since it is a multiple of its sum of digits (30).

It is not an unprimeable number, because it can be changed into a prime (13341124521121) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 964990 + ... + 5254850.

It is an arithmetic number, because the mean of its divisors is an integer number (129725426880).

Almost surely, 213341124521120 is an apocalyptic number.

13341124521120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13341124521120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (24907281960960).

13341124521120 is an abundant number, since it is smaller than the sum of its proper divisors (36473439400800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13341124521120 is a wasteful number, since it uses less digits than its factorization.

13341124521120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4289940 (or 4289932 counting only the distinct ones).

The product of its (nonzero) digits is 5760, while the sum is 30.

Adding to 13341124521120 its reverse (2112542114331), we get a palindrome (15453666635451).

The spelling of 13341124521120 in words is "thirteen trillion, three hundred forty-one billion, one hundred twenty-four million, five hundred twenty-one thousand, one hundred twenty".