Base | Representation |
---|---|
bin | 1100001000100011101000… |
… | …1011001001001101011110 |
3 | 1202020101211021220201021222 |
4 | 3002020322023021031132 |
5 | 3222040130432434324 |
6 | 44212500453253342 |
7 | 2544602665341611 |
oct | 302107213111536 |
9 | 52211737821258 |
10 | 13341144421214 |
11 | 4283a4724a695 |
12 | 15b572a334252 |
13 | 75a0ab9a129c |
14 | 341a01718178 |
15 | 18207903a55e |
hex | c223a2c935e |
13341144421214 has 8 divisors (see below), whose sum is σ = 20014234169400. Its totient is φ = 6669733031416.
The previous prime is 13341144421183. The next prime is 13341144421219. The reversal of 13341144421214 is 41212444114331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×133411444212142 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13341144421219) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 419569724 + ... + 419601519.
It is an arithmetic number, because the mean of its divisors is an integer number (2501779271175).
Almost surely, 213341144421214 is an apocalyptic number.
13341144421214 is a deficient number, since it is larger than the sum of its proper divisors (6673089748186).
13341144421214 is an equidigital number, since it uses as much as digits as its factorization.
13341144421214 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 839179194.
The product of its digits is 36864, while the sum is 35.
Adding to 13341144421214 its reverse (41212444114331), we get a palindrome (54553588535545).
The spelling of 13341144421214 in words is "thirteen trillion, three hundred forty-one billion, one hundred forty-four million, four hundred twenty-one thousand, two hundred fourteen".
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