Base | Representation |
---|---|
bin | 111110001000001110… |
… | …0111111000110100110 |
3 | 110202101021022021021012 |
4 | 1330100130333012212 |
5 | 4141221011121014 |
6 | 141143050022222 |
7 | 12432162313352 |
oct | 1742034770646 |
9 | 422337267235 |
10 | 133420020134 |
11 | 51646139955 |
12 | 21a36117972 |
13 | c7735b9c9b |
14 | 66597a8462 |
15 | 370d222c3e |
hex | 1f1073f1a6 |
133420020134 has 4 divisors (see below), whose sum is σ = 200130030204. Its totient is φ = 66710010066.
The previous prime is 133420020119. The next prime is 133420020187. The reversal of 133420020134 is 431020024331.
133420020134 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33355005032 + ... + 33355005035.
It is an arithmetic number, because the mean of its divisors is an integer number (50032507551).
Almost surely, 2133420020134 is an apocalyptic number.
133420020134 is a deficient number, since it is larger than the sum of its proper divisors (66710010070).
133420020134 is an equidigital number, since it uses as much as digits as its factorization.
133420020134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66710010069.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 133420020134 its reverse (431020024331), we get a palindrome (564440044465).
The spelling of 133420020134 in words is "one hundred thirty-three billion, four hundred twenty million, twenty thousand, one hundred thirty-four".
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