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1334214054550 = 2521331613373221
BaseRepresentation
bin10011011010100101010…
…110101101001010010110
311201112211200010111200201
4103122211112231022112
5133324432244221200
62500532433331114
7165252032225506
oct23324526551226
94645750114621
101334214054550
11474923061833
121966b5706a9a
1398a7b549430
144880d547a06
1524a8c9a7c6a
hex136a55ad296

1334214054550 has 192 divisors, whose sum is σ = 2813162946048. Its totient is φ = 467389440000.

The previous prime is 1334214054521. The next prime is 1334214054571. The reversal of 1334214054550 is 554504124331.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 414221940 + ... + 414225160.

It is an arithmetic number, because the mean of its divisors is an integer number (14651890344).

Almost surely, 21334214054550 is an apocalyptic number.

1334214054550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1334214054550 is an abundant number, since it is smaller than the sum of its proper divisors (1478948891498).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1334214054550 is a wasteful number, since it uses less digits than its factorization.

1334214054550 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3675 (or 3670 counting only the distinct ones).

The product of its (nonzero) digits is 144000, while the sum is 37.

Adding to 1334214054550 its reverse (554504124331), we get a palindrome (1888718178881).

The spelling of 1334214054550 in words is "one trillion, three hundred thirty-four billion, two hundred fourteen million, fifty-four thousand, five hundred fifty".