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13342153135 = 522718116491
BaseRepresentation
bin11000110110100000…
…10001100110101111
31021102211121121022211
430123100101212233
5204311042400020
610043532351251
7651426300433
oct143320214657
937384547284
1013342153135
115727330143
122704315527
13134823b38c
14907d929c3
155314da85a
hex31b4119af

13342153135 has 16 divisors (see below), whose sum is σ = 16092473472. Its totient is φ = 10619197600.

The previous prime is 13342153127. The next prime is 13342153141. The reversal of 13342153135 is 53135124331.

It is a happy number.

13342153135 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 13342153135 - 23 = 13342153127 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13342153097 and 13342153106.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2052240 + ... + 2058730.

It is an arithmetic number, because the mean of its divisors is an integer number (1005779592).

Almost surely, 213342153135 is an apocalyptic number.

13342153135 is a deficient number, since it is larger than the sum of its proper divisors (2750320337).

13342153135 is a wasteful number, since it uses less digits than its factorization.

13342153135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8534.

The product of its digits is 16200, while the sum is 31.

Adding to 13342153135 its reverse (53135124331), we get a palindrome (66477277466).

The spelling of 13342153135 in words is "thirteen billion, three hundred forty-two million, one hundred fifty-three thousand, one hundred thirty-five".

Divisors: 1 5 227 1135 1811 6491 9055 32455 411097 1473457 2055485 7367285 11755201 58776005 2668430627 13342153135