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13342204320044 = 2229115019002759
BaseRepresentation
bin1100001000100111100101…
…0110010101100100101100
31202020111120011022011011012
43002021321112111210230
53222044313301220134
644213153554444352
72544641155335635
oct302117126254454
952214504264135
1013342204320044
114284440565336
1215b59852936b8
1375a21a451362
14341aa23b888c
151820dc0ee6ce
hexc227959592c

13342204320044 has 12 divisors (see below), whose sum is σ = 24153990579600. Its totient is φ = 6441064154448.

The previous prime is 13342204319987. The next prime is 13342204320047. The reversal of 13342204320044 is 44002340224331.

It is a super-2 number, since 2×133422043200442 (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13342204320047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57509501264 + ... + 57509501495.

It is an arithmetic number, because the mean of its divisors is an integer number (2012832548300).

Almost surely, 213342204320044 is an apocalyptic number.

It is an amenable number.

13342204320044 is a deficient number, since it is larger than the sum of its proper divisors (10811786259556).

13342204320044 is a wasteful number, since it uses less digits than its factorization.

13342204320044 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 115019002792 (or 115019002790 counting only the distinct ones).

The product of its (nonzero) digits is 55296, while the sum is 32.

Adding to 13342204320044 its reverse (44002340224331), we get a palindrome (57344544544375).

The spelling of 13342204320044 in words is "thirteen trillion, three hundred forty-two billion, two hundred four million, three hundred twenty thousand, forty-four".

Divisors: 1 2 4 29 58 116 115019002759 230038005518 460076011036 3335551080011 6671102160022 13342204320044