Base | Representation |
---|---|
bin | 1100001000100111111111… |
… | …0101010110101001011001 |
3 | 1202020111211202000110200102 |
4 | 3002021333311112221121 |
5 | 3222100024124123301 |
6 | 44213212442345145 |
7 | 2544643646146031 |
oct | 302117765265131 |
9 | 52214752013612 |
10 | 13342313114201 |
11 | 4284496a12a65 |
12 | 15b59b57bb1b5 |
13 | 75a236b538b6 |
14 | 341ab2a188c1 |
15 | 1820e693eb6b |
hex | c227fd56a59 |
13342313114201 has 2 divisors, whose sum is σ = 13342313114202. Its totient is φ = 13342313114200.
The previous prime is 13342313114197. The next prime is 13342313114243. The reversal of 13342313114201 is 10241131324331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12897292038400 + 445021075801 = 3591280^2 + 667099^2 .
It is a cyclic number.
It is not a de Polignac number, because 13342313114201 - 22 = 13342313114197 is a prime.
It is not a weakly prime, because it can be changed into another prime (13342313114701) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6671156557100 + 6671156557101.
It is an arithmetic number, because the mean of its divisors is an integer number (6671156557101).
Almost surely, 213342313114201 is an apocalyptic number.
It is an amenable number.
13342313114201 is a deficient number, since it is larger than the sum of its proper divisors (1).
13342313114201 is an equidigital number, since it uses as much as digits as its factorization.
13342313114201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 13342313114201 its reverse (10241131324331), we get a palindrome (23583444438532).
The spelling of 13342313114201 in words is "thirteen trillion, three hundred forty-two billion, three hundred thirteen million, one hundred fourteen thousand, two hundred one".
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