133423201411140 has 384 divisors, whose sum is σ = 410579095449600. Its totient is φ = 32261516550144.

The previous prime is 133423201411121. The next prime is 133423201411151. The reversal of 133423201411140 is 41114102324331.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 133423201411098 and 133423201411107.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 11915972022 + ... + 11915983218.

It is an arithmetic number, because the mean of its divisors is an integer number (1069216394400).

Almost surely, 2^{133423201411140} is an apocalyptic number.

133423201411140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 133423201411140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (205289547724800).

133423201411140 is an abundant number, since it is smaller than the sum of its proper divisors (277155894038460).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133423201411140 is a wasteful number, since it uses less digits than its factorization.

133423201411140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11792 (or 11732 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 30.

Adding to 133423201411140 its reverse (41114102324331), we get a palindrome (174537303735471).

The spelling of 133423201411140 in words is "one hundred thirty-three trillion, four hundred twenty-three billion, two hundred one million, four hundred eleven thousand, one hundred forty".