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13342504963 is a prime number
BaseRepresentation
bin11000110110100011…
…00111100000000011
31021102212021110221111
430123101213200003
5204311140124323
610043544104151
7651432264244
oct143321474003
937385243844
1013342504963
115727550507
122704465057
131348332568
14908044ccb
15531559c0d
hex31b467803

13342504963 has 2 divisors, whose sum is σ = 13342504964. Its totient is φ = 13342504962.

The previous prime is 13342504921. The next prime is 13342505009. The reversal of 13342504963 is 36940524331.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13342504963 - 213 = 13342496771 is a prime.

It is not a weakly prime, because it can be changed into another prime (13342507963) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6671252481 + 6671252482.

It is an arithmetic number, because the mean of its divisors is an integer number (6671252482).

Almost surely, 213342504963 is an apocalyptic number.

13342504963 is a deficient number, since it is larger than the sum of its proper divisors (1).

13342504963 is an equidigital number, since it uses as much as digits as its factorization.

13342504963 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 233280, while the sum is 40.

The spelling of 13342504963 in words is "thirteen billion, three hundred forty-two million, five hundred four thousand, nine hundred sixty-three".