Base | Representation |
---|---|
bin | 1100001000101010100110… |
… | …0100000011101110101101 |
3 | 1202020120122112101200212120 |
4 | 3002022221210003232231 |
5 | 3222102442341121331 |
6 | 44213410132223153 |
7 | 2545000210033404 |
oct | 302125144035655 |
9 | 52216575350776 |
10 | 13343013223341 |
11 | 428481612735a |
12 | 15b5b7016aab9 |
13 | 75a318c00869 |
14 | 341b3b9c063b |
15 | 182138134796 |
hex | c22a9903bad |
13343013223341 has 4 divisors (see below), whose sum is σ = 17790684297792. Its totient is φ = 8895342148892.
The previous prime is 13343013223313. The next prime is 13343013223363. The reversal of 13343013223341 is 14332231034331.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13343013223341 - 210 = 13343013222317 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13343013223301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2223835537221 + ... + 2223835537226.
It is an arithmetic number, because the mean of its divisors is an integer number (4447671074448).
Almost surely, 213343013223341 is an apocalyptic number.
It is an amenable number.
13343013223341 is a deficient number, since it is larger than the sum of its proper divisors (4447671074451).
13343013223341 is an equidigital number, since it uses as much as digits as its factorization.
13343013223341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4447671074450.
The product of its (nonzero) digits is 46656, while the sum is 33.
Adding to 13343013223341 its reverse (14332231034331), we get a palindrome (27675244257672).
The spelling of 13343013223341 in words is "thirteen trillion, three hundred forty-three billion, thirteen million, two hundred twenty-three thousand, three hundred forty-one".
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