Base | Representation |
---|---|
bin | 10011011010101100010… |
… | …101101011000100010110 |
3 | 11201120010211121100102122 |
4 | 103122230111223010112 |
5 | 133330202243134332 |
6 | 2500552220535542 |
7 | 165254654161424 |
oct | 23325425530426 |
9 | 4646124540378 |
10 | 1334331224342 |
11 | 474983210176 |
12 | 1967289b15b2 |
13 | 98a998c207c |
14 | 48820d28114 |
15 | 24a97deec12 |
hex | 136ac56b116 |
1334331224342 has 4 divisors (see below), whose sum is σ = 2001496836516. Its totient is φ = 667165612170.
The previous prime is 1334331224309. The next prime is 1334331224371. The reversal of 1334331224342 is 2434221334331.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 333582806084 + ... + 333582806087.
It is an arithmetic number, because the mean of its divisors is an integer number (500374209129).
Almost surely, 21334331224342 is an apocalyptic number.
1334331224342 is a deficient number, since it is larger than the sum of its proper divisors (667165612174).
1334331224342 is an equidigital number, since it uses as much as digits as its factorization.
1334331224342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 667165612173.
The product of its digits is 124416, while the sum is 35.
Adding to 1334331224342 its reverse (2434221334331), we get a palindrome (3768552558673).
The spelling of 1334331224342 in words is "one trillion, three hundred thirty-four billion, three hundred thirty-one million, two hundred twenty-four thousand, three hundred forty-two".
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