Base | Representation |
---|---|
bin | 11000110110101001… |
… | …01111010001101001 |
3 | 1021102220211001102002 |
4 | 30123110233101221 |
5 | 204311342320431 |
6 | 10044013420345 |
7 | 651442243013 |
oct | 143324572151 |
9 | 37386731362 |
10 | 13343323241 |
11 | 5727a5a276 |
12 | 270479a6b5 |
13 | 134855ab51 |
14 | 9081b91b3 |
15 | 53166c3cb |
hex | 31b52f469 |
13343323241 has 2 divisors, whose sum is σ = 13343323242. Its totient is φ = 13343323240.
The previous prime is 13343323193. The next prime is 13343323261. The reversal of 13343323241 is 14232334331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13218330841 + 124992400 = 114971^2 + 11180^2 .
It is a cyclic number.
It is not a de Polignac number, because 13343323241 - 214 = 13343306857 is a prime.
It is a super-2 number, since 2×133433232412 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13343323261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6671661620 + 6671661621.
It is an arithmetic number, because the mean of its divisors is an integer number (6671661621).
Almost surely, 213343323241 is an apocalyptic number.
It is an amenable number.
13343323241 is a deficient number, since it is larger than the sum of its proper divisors (1).
13343323241 is an equidigital number, since it uses as much as digits as its factorization.
13343323241 is an evil number, because the sum of its binary digits is even.
The product of its digits is 15552, while the sum is 29.
Adding to 13343323241 its reverse (14232334331), we get a palindrome (27575657572).
The spelling of 13343323241 in words is "thirteen billion, three hundred forty-three million, three hundred twenty-three thousand, two hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.064 sec. • engine limits •