Base | Representation |
---|---|
bin | 11000110110101001… |
… | …10101110111000100 |
3 | 1021102220212102102000 |
4 | 30123110311313010 |
5 | 204311344201322 |
6 | 10044014145300 |
7 | 651442414443 |
oct | 143324656704 |
9 | 37386772360 |
10 | 13343350212 |
11 | 5727a78565 |
12 | 27047b2230 |
13 | 134856a1ca |
14 | 9081c4d5a |
15 | 5316753ac |
hex | 31b535dc4 |
13343350212 has 48 divisors (see below), whose sum is σ = 35709811200. Its totient is φ = 4304305440.
The previous prime is 13343350211. The next prime is 13343350301. The reversal of 13343350212 is 21205334331.
13343350212 is a `hidden beast` number, since 13 + 3 + 433 + 5 + 0 + 212 = 666.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is not an unprimeable number, because it can be changed into a prime (13343350211) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1989387 + ... + 1996082.
It is an arithmetic number, because the mean of its divisors is an integer number (743954400).
Almost surely, 213343350212 is an apocalyptic number.
13343350212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
13343350212 is an abundant number, since it is smaller than the sum of its proper divisors (22366460988).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13343350212 is a wasteful number, since it uses less digits than its factorization.
13343350212 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3985513 (or 3985505 counting only the distinct ones).
The product of its (nonzero) digits is 6480, while the sum is 27.
Adding to 13343350212 its reverse (21205334331), we get a palindrome (34548684543).
The spelling of 13343350212 in words is "thirteen billion, three hundred forty-three million, three hundred fifty thousand, two hundred twelve".
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