133434403421 has 4 divisors (see below), whose sum is σ = 145564803744. Its totient is φ = 121304003100.

The previous prime is 133434403411. The next prime is 133434403429. The reversal of 133434403421 is 124304434331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-133434403421 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133434403429) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6065200145 + ... + 6065200166.

It is an arithmetic number, because the mean of its divisors is an integer number (36391200936).

Almost surely, 2^133434403421 is an apocalyptic number.

133434403421 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

133434403421 is a deficient number, since it is larger than the sum of its proper divisors (12130400323).

133434403421 is a wasteful number, since it uses less digits than its factorization.

133434403421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12130400322.

The product of its (nonzero) digits is 41472, while the sum is 32.

Adding to 133434403421 its reverse (124304434331), we get a palindrome (257738837752).

The spelling of 133434403421 in words is "one hundred thirty-three billion, four hundred thirty-four million, four hundred three thousand, four hundred twenty-one".