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13344024220019 is a prime number
BaseRepresentation
bin1100001000101110010111…
…0100101101000101110011
31202020200020222202122120222
43002023211310231011303
53222112030200020034
644214054325323255
72545034234254523
oct302134564550563
952220228678528
1013344024220019
1142851948810a9
1215b61b286652b
1375a44a4bb14c
14341bd5d91683
15182196c8912e
hexc22e5d2d173

13344024220019 has 2 divisors, whose sum is σ = 13344024220020. Its totient is φ = 13344024220018.

The previous prime is 13344024219989. The next prime is 13344024220027. The reversal of 13344024220019 is 91002242044331.

13344024220019 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13344024220019 is a prime.

It is a super-2 number, since 2×133440242200192 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13344024220069) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6672012110009 + 6672012110010.

It is an arithmetic number, because the mean of its divisors is an integer number (6672012110010).

Almost surely, 213344024220019 is an apocalyptic number.

13344024220019 is a deficient number, since it is larger than the sum of its proper divisors (1).

13344024220019 is an equidigital number, since it uses as much as digits as its factorization.

13344024220019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41472, while the sum is 35.

The spelling of 13344024220019 in words is "thirteen trillion, three hundred forty-four billion, twenty-four million, two hundred twenty thousand, nineteen".