Base | Representation |
---|---|
bin | 1100001000101110010111… |
… | …0100101101000101110011 |
3 | 1202020200020222202122120222 |
4 | 3002023211310231011303 |
5 | 3222112030200020034 |
6 | 44214054325323255 |
7 | 2545034234254523 |
oct | 302134564550563 |
9 | 52220228678528 |
10 | 13344024220019 |
11 | 42851948810a9 |
12 | 15b61b286652b |
13 | 75a44a4bb14c |
14 | 341bd5d91683 |
15 | 182196c8912e |
hex | c22e5d2d173 |
13344024220019 has 2 divisors, whose sum is σ = 13344024220020. Its totient is φ = 13344024220018.
The previous prime is 13344024219989. The next prime is 13344024220027. The reversal of 13344024220019 is 91002242044331.
13344024220019 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13344024220019 is a prime.
It is a super-2 number, since 2×133440242200192 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13344024220069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6672012110009 + 6672012110010.
It is an arithmetic number, because the mean of its divisors is an integer number (6672012110010).
Almost surely, 213344024220019 is an apocalyptic number.
13344024220019 is a deficient number, since it is larger than the sum of its proper divisors (1).
13344024220019 is an equidigital number, since it uses as much as digits as its factorization.
13344024220019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 35.
The spelling of 13344024220019 in words is "thirteen trillion, three hundred forty-four billion, twenty-four million, two hundred twenty thousand, nineteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •