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13345194131 is a prime number
BaseRepresentation
bin11000110110110111…
…11000000010010011
31021110001100002210022
430123123320002103
5204312332203011
610044121454055
7651464164343
oct143333700223
937401302708
1013345194131
115729017965
12270534132b
131348a64599
14908544d23
155318db8db
hex31b6f8093

13345194131 has 2 divisors, whose sum is σ = 13345194132. Its totient is φ = 13345194130.

The previous prime is 13345194127. The next prime is 13345194143. The reversal of 13345194131 is 13149154331.

13345194131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13345194131 - 22 = 13345194127 is a prime.

It is a super-2 number, since 2×133451941312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13345194091 and 13345194100.

It is not a weakly prime, because it can be changed into another prime (13345194101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6672597065 + 6672597066.

It is an arithmetic number, because the mean of its divisors is an integer number (6672597066).

Almost surely, 213345194131 is an apocalyptic number.

13345194131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13345194131 is an equidigital number, since it uses as much as digits as its factorization.

13345194131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 19440, while the sum is 35.

The spelling of 13345194131 in words is "thirteen billion, three hundred forty-five million, one hundred ninety-four thousand, one hundred thirty-one".