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13345425405491 is a prime number
BaseRepresentation
bin1100001000110011100101…
…0101110011011000110011
31202020210212122100020201012
43002030321111303120303
53222122412400433431
644214445341501135
72545114040165414
oct302147125633063
952223778306635
1013345425405491
1142858437aa523
1215b6523b717ab
1375a61189338a
14341cca0d180b
15182229cb522b
hexc2339573633

13345425405491 has 2 divisors, whose sum is σ = 13345425405492. Its totient is φ = 13345425405490.

The previous prime is 13345425405419. The next prime is 13345425405509. The reversal of 13345425405491 is 19450452454331.

13345425405491 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (13345425405419) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (19450452454331) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13345425405491 is a prime.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (13345425405791) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6672712702745 + 6672712702746.

It is an arithmetic number, because the mean of its divisors is an integer number (6672712702746).

Almost surely, 213345425405491 is an apocalyptic number.

13345425405491 is a deficient number, since it is larger than the sum of its proper divisors (1).

13345425405491 is an equidigital number, since it uses as much as digits as its factorization.

13345425405491 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184000, while the sum is 50.

The spelling of 13345425405491 in words is "thirteen trillion, three hundred forty-five billion, four hundred twenty-five million, four hundred five thousand, four hundred ninety-one".