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133456414440619 is a prime number
BaseRepresentation
bin11110010110000010111110…
…001011001111110010101011
3122111112022022222120110011101
4132112002332023033302223
5114443022214044044434
61151501010322542231
740052623234535434
oct3626027613176253
9574468288513141
10133456414440619
1139583602828546
1212b748b7207977
135960b6938831a
1424d547983a48b
15106679327ab14
hex7960be2cfcab

133456414440619 has 2 divisors, whose sum is σ = 133456414440620. Its totient is φ = 133456414440618.

The previous prime is 133456414440571. The next prime is 133456414440649. The reversal of 133456414440619 is 916044414654331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 133456414440619 - 227 = 133456280222891 is a prime.

It is a super-2 number, since 2×1334564144406192 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 133456414440619.

It is not a weakly prime, because it can be changed into another prime (133456414440649) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66728207220309 + 66728207220310.

It is an arithmetic number, because the mean of its divisors is an integer number (66728207220310).

Almost surely, 2133456414440619 is an apocalyptic number.

133456414440619 is a deficient number, since it is larger than the sum of its proper divisors (1).

133456414440619 is an equidigital number, since it uses as much as digits as its factorization.

133456414440619 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14929920, while the sum is 55.

The spelling of 133456414440619 in words is "one hundred thirty-three trillion, four hundred fifty-six billion, four hundred fourteen million, four hundred forty thousand, six hundred nineteen".