Base | Representation |
---|---|
bin | 11110010110000010111110… |
… | …001011001111110010101011 |
3 | 122111112022022222120110011101 |
4 | 132112002332023033302223 |
5 | 114443022214044044434 |
6 | 1151501010322542231 |
7 | 40052623234535434 |
oct | 3626027613176253 |
9 | 574468288513141 |
10 | 133456414440619 |
11 | 39583602828546 |
12 | 12b748b7207977 |
13 | 5960b6938831a |
14 | 24d547983a48b |
15 | 106679327ab14 |
hex | 7960be2cfcab |
133456414440619 has 2 divisors, whose sum is σ = 133456414440620. Its totient is φ = 133456414440618.
The previous prime is 133456414440571. The next prime is 133456414440649. The reversal of 133456414440619 is 916044414654331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133456414440619 - 227 = 133456280222891 is a prime.
It is a super-2 number, since 2×1334564144406192 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 133456414440619.
It is not a weakly prime, because it can be changed into another prime (133456414440649) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66728207220309 + 66728207220310.
It is an arithmetic number, because the mean of its divisors is an integer number (66728207220310).
Almost surely, 2133456414440619 is an apocalyptic number.
133456414440619 is a deficient number, since it is larger than the sum of its proper divisors (1).
133456414440619 is an equidigital number, since it uses as much as digits as its factorization.
133456414440619 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14929920, while the sum is 55.
The spelling of 133456414440619 in words is "one hundred thirty-three trillion, four hundred fifty-six billion, four hundred fourteen million, four hundred forty thousand, six hundred nineteen".
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