Base | Representation |
---|---|
bin | 11110010110001010111110… |
… | …101101110001000001111111 |
3 | 122111120010112021002002010210 |
4 | 132112022332231301001333 |
5 | 114443142321414034010 |
6 | 1151504551501003503 |
7 | 40053346310642532 |
oct | 3626127655610177 |
9 | 574503467062123 |
10 | 133465013424255 |
11 | 3958721571a197 |
12 | 12b764b6b53593 |
13 | 5961909a2c516 |
14 | 24d5a538a4a19 |
15 | 1066ae8142b20 |
hex | 7962beb7107f |
133465013424255 has 8 divisors (see below), whose sum is σ = 213544021478832. Its totient is φ = 71181340492928.
The previous prime is 133465013424241. The next prime is 133465013424311. The reversal of 133465013424255 is 552424310564331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 133465013424255 - 28 = 133465013423999 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4448833780794 + ... + 4448833780823.
It is an arithmetic number, because the mean of its divisors is an integer number (26693002684854).
Almost surely, 2133465013424255 is an apocalyptic number.
133465013424255 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
133465013424255 is a deficient number, since it is larger than the sum of its proper divisors (80079008054577).
133465013424255 is an equidigital number, since it uses as much as digits as its factorization.
133465013424255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8897667561625.
The product of its (nonzero) digits is 5184000, while the sum is 48.
Adding to 133465013424255 its reverse (552424310564331), we get a palindrome (685889323988586).
The spelling of 133465013424255 in words is "one hundred thirty-three trillion, four hundred sixty-five billion, thirteen million, four hundred twenty-four thousand, two hundred fifty-five".
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