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133465013424311 is a prime number
BaseRepresentation
bin11110010110001010111110…
…101101110001000010110111
3122111120010112021002002012212
4132112022332231301002313
5114443142321414034221
61151504551501004035
740053346310642642
oct3626127655610267
9574503467062185
10133465013424311
113958721571a238
1212b764b6b5361b
135961909a2c55a
1424d5a538a4a59
151066ae8142b5b
hex7962beb710b7

133465013424311 has 2 divisors, whose sum is σ = 133465013424312. Its totient is φ = 133465013424310.

The previous prime is 133465013424241. The next prime is 133465013424317. The reversal of 133465013424311 is 113424310564331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 133465013424311 - 242 = 129066966913207 is a prime.

It is a super-3 number, since 3×1334650134243113 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133465013424317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66732506712155 + 66732506712156.

It is an arithmetic number, because the mean of its divisors is an integer number (66732506712156).

Almost surely, 2133465013424311 is an apocalyptic number.

133465013424311 is a deficient number, since it is larger than the sum of its proper divisors (1).

133465013424311 is an equidigital number, since it uses as much as digits as its factorization.

133465013424311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 311040, while the sum is 41.

Adding to 133465013424311 its reverse (113424310564331), we get a palindrome (246889323988642).

The spelling of 133465013424311 in words is "one hundred thirty-three trillion, four hundred sixty-five billion, thirteen million, four hundred twenty-four thousand, three hundred eleven".