Base | Representation |
---|---|
bin | 11110010110001010111110… |
… | …101101110001000010110111 |
3 | 122111120010112021002002012212 |
4 | 132112022332231301002313 |
5 | 114443142321414034221 |
6 | 1151504551501004035 |
7 | 40053346310642642 |
oct | 3626127655610267 |
9 | 574503467062185 |
10 | 133465013424311 |
11 | 3958721571a238 |
12 | 12b764b6b5361b |
13 | 5961909a2c55a |
14 | 24d5a538a4a59 |
15 | 1066ae8142b5b |
hex | 7962beb710b7 |
133465013424311 has 2 divisors, whose sum is σ = 133465013424312. Its totient is φ = 133465013424310.
The previous prime is 133465013424241. The next prime is 133465013424317. The reversal of 133465013424311 is 113424310564331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133465013424311 - 242 = 129066966913207 is a prime.
It is a super-3 number, since 3×1334650134243113 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133465013424317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66732506712155 + 66732506712156.
It is an arithmetic number, because the mean of its divisors is an integer number (66732506712156).
Almost surely, 2133465013424311 is an apocalyptic number.
133465013424311 is a deficient number, since it is larger than the sum of its proper divisors (1).
133465013424311 is an equidigital number, since it uses as much as digits as its factorization.
133465013424311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 311040, while the sum is 41.
Adding to 133465013424311 its reverse (113424310564331), we get a palindrome (246889323988642).
The spelling of 133465013424311 in words is "one hundred thirty-three trillion, four hundred sixty-five billion, thirteen million, four hundred twenty-four thousand, three hundred eleven".
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