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1334712171643 is a prime number
BaseRepresentation
bin10011011011000011000…
…010110111110001111011
311201121010101102110212221
4103123003002313301323
5133331442303443033
62501054105544511
7165300261161104
oct23330302676173
94647111373787
101334712171643
11475059252554
121968144a5137
1398b2a7c2486
144885976d3ab
1524abb59d12d
hex136c30b7c7b

1334712171643 has 2 divisors, whose sum is σ = 1334712171644. Its totient is φ = 1334712171642.

The previous prime is 1334712171619. The next prime is 1334712171671. The reversal of 1334712171643 is 3461712174331.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1334712171643 is a prime.

It is a super-2 number, since 2×13347121716432 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1334712171643.

It is not a weakly prime, because it can be changed into another prime (1334712121643) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667356085821 + 667356085822.

It is an arithmetic number, because the mean of its divisors is an integer number (667356085822).

Almost surely, 21334712171643 is an apocalyptic number.

1334712171643 is a deficient number, since it is larger than the sum of its proper divisors (1).

1334712171643 is an equidigital number, since it uses as much as digits as its factorization.

1334712171643 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 254016, while the sum is 43.

The spelling of 1334712171643 in words is "one trillion, three hundred thirty-four billion, seven hundred twelve million, one hundred seventy-one thousand, six hundred forty-three".