Base | Representation |
---|---|
bin | 11110010110101011111001… |
… | …000101101010101011100001 |
3 | 122111200111202002210110121012 |
4 | 132112223321011222223201 |
5 | 114444232210220202333 |
6 | 1151533114300110305 |
7 | 40056040121122232 |
oct | 3626537105525341 |
9 | 574614662713535 |
10 | 133500352506593 |
11 | 395a01aa708866 |
12 | 12b81319b35395 |
13 | 596504c285c27 |
14 | 24d7647039089 |
15 | 10679b5851e48 |
hex | 796af916aae1 |
133500352506593 has 2 divisors, whose sum is σ = 133500352506594. Its totient is φ = 133500352506592.
The previous prime is 133500352506589. The next prime is 133500352506637. The reversal of 133500352506593 is 395605253005331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 121427000049664 + 12073352456929 = 11019392^2 + 3474673^2 .
It is an emirp because it is prime and its reverse (395605253005331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133500352506593 - 22 = 133500352506589 is a prime.
It is not a weakly prime, because it can be changed into another prime (133500352406593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66750176253296 + 66750176253297.
It is an arithmetic number, because the mean of its divisors is an integer number (66750176253297).
Almost surely, 2133500352506593 is an apocalyptic number.
It is an amenable number.
133500352506593 is a deficient number, since it is larger than the sum of its proper divisors (1).
133500352506593 is an equidigital number, since it uses as much as digits as its factorization.
133500352506593 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5467500, while the sum is 50.
The spelling of 133500352506593 in words is "one hundred thirty-three trillion, five hundred billion, three hundred fifty-two million, five hundred six thousand, five hundred ninety-three".
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