Base | Representation |
---|---|
bin | 11110010110110110001000… |
… | …010000001100010011100001 |
3 | 122111201120010010212120110012 |
4 | 132112312020100030103201 |
5 | 114444422213122422431 |
6 | 1151542133113214305 |
7 | 40056606401152265 |
oct | 3626661020142341 |
9 | 574646103776405 |
10 | 133511344342241 |
11 | 395a493027a658 |
12 | 12b83487101395 |
13 | 59660b15b23a8 |
14 | 24d7daabc20a5 |
15 | 1067e0a82c22b |
hex | 796d8840c4e1 |
133511344342241 has 2 divisors, whose sum is σ = 133511344342242. Its totient is φ = 133511344342240.
The previous prime is 133511344342177. The next prime is 133511344342247. The reversal of 133511344342241 is 142243443115331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 131900539161616 + 1610805180625 = 11484796^2 + 1269175^2 .
It is a cyclic number.
It is not a de Polignac number, because 133511344342241 - 26 = 133511344342177 is a prime.
It is not a weakly prime, because it can be changed into another prime (133511344342247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66755672171120 + 66755672171121.
It is an arithmetic number, because the mean of its divisors is an integer number (66755672171121).
Almost surely, 2133511344342241 is an apocalyptic number.
It is an amenable number.
133511344342241 is a deficient number, since it is larger than the sum of its proper divisors (1).
133511344342241 is an equidigital number, since it uses as much as digits as its factorization.
133511344342241 is an evil number, because the sum of its binary digits is even.
The product of its digits is 414720, while the sum is 41.
Adding to 133511344342241 its reverse (142243443115331), we get a palindrome (275754787457572).
The spelling of 133511344342241 in words is "one hundred thirty-three trillion, five hundred eleven billion, three hundred forty-four million, three hundred forty-two thousand, two hundred forty-one".
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