Search a number
-
+
13351445503 = 119871122963
BaseRepresentation
bin11000110111100111…
…01110001111111111
31021110111002201001121
430123303232033333
5204320432224003
610044503451411
7651601262044
oct143363561777
937414081047
1013351445503
1157315a7690
122707456b67
13134a142b16
149092d11cb
15532223cbd
hex31bcee3ff

13351445503 has 8 divisors (see below), whose sum is σ = 14566807296. Its totient is φ = 12136349400.

The previous prime is 13351445501. The next prime is 13351445507. The reversal of 13351445503 is 30554415331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13351445503 - 21 = 13351445501 is a prime.

It is a super-2 number, since 2×133514455032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13351445501) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47100 + ... + 170062.

It is an arithmetic number, because the mean of its divisors is an integer number (1820850912).

Almost surely, 213351445503 is an apocalyptic number.

13351445503 is a deficient number, since it is larger than the sum of its proper divisors (1215361793).

13351445503 is a wasteful number, since it uses less digits than its factorization.

13351445503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 132845.

The product of its (nonzero) digits is 54000, while the sum is 34.

It can be divided in two parts, 13351 and 445503, that added together give a palindrome (458854).

The spelling of 13351445503 in words is "thirteen billion, three hundred fifty-one million, four hundred forty-five thousand, five hundred three".

Divisors: 1 11 9871 108581 122963 1352593 1213767773 13351445503