Base | Representation |
---|---|
bin | 1100001001001010000010… |
… | …0111110010100110100110 |
3 | 1202021101102201120221220211 |
4 | 3002102200213302212212 |
5 | 3222222234001011124 |
6 | 44221323425050034 |
7 | 2545416312122503 |
oct | 302224047624646 |
9 | 52241381527824 |
10 | 13351453141414 |
11 | 4288357254763 |
12 | 15b772678691a |
13 | 75b06262071b |
14 | 3422dc8804aa |
15 | 18247e07ae94 |
hex | c24a09f29a6 |
13351453141414 has 4 divisors (see below), whose sum is σ = 20027179712124. Its totient is φ = 6675726570706.
The previous prime is 13351453141381. The next prime is 13351453141417. The reversal of 13351453141414 is 41414135415331.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×133514531414142 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13351453141417) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3337863285352 + ... + 3337863285355.
It is an arithmetic number, because the mean of its divisors is an integer number (5006794928031).
Almost surely, 213351453141414 is an apocalyptic number.
13351453141414 is a deficient number, since it is larger than the sum of its proper divisors (6675726570710).
13351453141414 is an equidigital number, since it uses as much as digits as its factorization.
13351453141414 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6675726570709.
The product of its digits is 172800, while the sum is 40.
Adding to 13351453141414 its reverse (41414135415331), we get a palindrome (54765588556745).
The spelling of 13351453141414 in words is "thirteen trillion, three hundred fifty-one billion, four hundred fifty-three million, one hundred forty-one thousand, four hundred fourteen".
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