Base | Representation |
---|---|
bin | 111110001011000100… |
… | …0010000110111010001 |
3 | 110202121220111111122222 |
4 | 1330112020100313101 |
5 | 4141414401014103 |
6 | 141200331110425 |
7 | 12434426623664 |
oct | 1742610206721 |
9 | 422556444588 |
10 | 133515251153 |
11 | 51694973379 |
12 | 21a61ba2415 |
13 | c78a250bbb |
14 | 66682b76db |
15 | 3716784638 |
hex | 1f16210dd1 |
133515251153 has 2 divisors, whose sum is σ = 133515251154. Its totient is φ = 133515251152.
The previous prime is 133515251147. The next prime is 133515251167. The reversal of 133515251153 is 351152515331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 126033520144 + 7481731009 = 355012^2 + 86497^2 .
It is a cyclic number.
It is not a de Polignac number, because 133515251153 - 210 = 133515250129 is a prime.
It is not a weakly prime, because it can be changed into another prime (133515251113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66757625576 + 66757625577.
It is an arithmetic number, because the mean of its divisors is an integer number (66757625577).
Almost surely, 2133515251153 is an apocalyptic number.
It is an amenable number.
133515251153 is a deficient number, since it is larger than the sum of its proper divisors (1).
133515251153 is an equidigital number, since it uses as much as digits as its factorization.
133515251153 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 33750, while the sum is 35.
Adding to 133515251153 its reverse (351152515331), we get a palindrome (484667766484).
The spelling of 133515251153 in words is "one hundred thirty-three billion, five hundred fifteen million, two hundred fifty-one thousand, one hundred fifty-three".
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