Base | Representation |
---|---|
bin | 11000110111101000… |
… | …00101101001001001 |
3 | 1021110111021120111102 |
4 | 30123310011221021 |
5 | 204320443310241 |
6 | 10044505511145 |
7 | 651602141306 |
oct | 143364055111 |
9 | 37414246442 |
10 | 13351541321 |
11 | 5731662678 |
12 | 27074a24b5 |
13 | 134a177611 |
14 | 9093180ad |
15 | 53224239b |
hex | 31bd05a49 |
13351541321 has 2 divisors, whose sum is σ = 13351541322. Its totient is φ = 13351541320.
The previous prime is 13351541303. The next prime is 13351541327. The reversal of 13351541321 is 12314515331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12378787600 + 972753721 = 111260^2 + 31189^2 .
It is an emirp because it is prime and its reverse (12314515331) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13351541321 is a prime.
It is not a weakly prime, because it can be changed into another prime (13351541327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6675770660 + 6675770661.
It is an arithmetic number, because the mean of its divisors is an integer number (6675770661).
Almost surely, 213351541321 is an apocalyptic number.
It is an amenable number.
13351541321 is a deficient number, since it is larger than the sum of its proper divisors (1).
13351541321 is an equidigital number, since it uses as much as digits as its factorization.
13351541321 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5400, while the sum is 29.
The spelling of 13351541321 in words is "thirteen billion, three hundred fifty-one million, five hundred forty-one thousand, three hundred twenty-one".
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