13352041524341 has 4 divisors (see below), whose sum is σ = 14379121641612. Its totient is φ = 12324961407072.

The previous prime is 13352041524317. The next prime is 13352041524461. The reversal of 13352041524341 is 14342514025331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3291789720241 + 10060251804100 = 1814329^2 + 3171790^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13352041524341 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13352041524295 and 13352041524304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13352041524301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 513540058616 + ... + 513540058641.

It is an arithmetic number, because the mean of its divisors is an integer number (3594780410403).

Almost surely, 2^{13352041524341} is an apocalyptic number.

It is an amenable number.

13352041524341 is a deficient number, since it is larger than the sum of its proper divisors (1027080117271).

13352041524341 is a wasteful number, since it uses less digits than its factorization.

13352041524341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1027080117270.

The product of its (nonzero) digits is 172800, while the sum is 38.

Adding to 13352041524341 its reverse (14342514025331), we get a palindrome (27694555549672).

The spelling of 13352041524341 in words is "thirteen trillion, three hundred fifty-two billion, forty-one million, five hundred twenty-four thousand, three hundred forty-one".