Base | Representation |
---|---|
bin | 111110001011001110… |
… | …0110010011010010101 |
3 | 110202122021121212001001 |
4 | 1330112130302122111 |
5 | 4141422240201240 |
6 | 141201042303301 |
7 | 12434523432655 |
oct | 1742634623225 |
9 | 422567555031 |
10 | 133520631445 |
11 | 51697a086a3 |
12 | 21a63957b31 |
13 | c78b3b5ac6 |
14 | 6668cb8365 |
15 | 3716e9889a |
hex | 1f16732695 |
133520631445 has 48 divisors (see below), whose sum is σ = 175248783360. Its totient is φ = 97528572288.
The previous prime is 133520631443. The next prime is 133520631469. The reversal of 133520631445 is 544136025331.
It is not a de Polignac number, because 133520631445 - 21 = 133520631443 is a prime.
It is a super-3 number, since 3×1335206314453 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133520631443) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 33655852 + ... + 33659818.
It is an arithmetic number, because the mean of its divisors is an integer number (3651016320).
Almost surely, 2133520631445 is an apocalyptic number.
It is an amenable number.
133520631445 is a deficient number, since it is larger than the sum of its proper divisors (41728151915).
133520631445 is a wasteful number, since it uses less digits than its factorization.
133520631445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4682 (or 4663 counting only the distinct ones).
The product of its (nonzero) digits is 129600, while the sum is 37.
Adding to 133520631445 its reverse (544136025331), we get a palindrome (677656656776).
The spelling of 133520631445 in words is "one hundred thirty-three billion, five hundred twenty million, six hundred thirty-one thousand, four hundred forty-five".
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