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13352115224103 = 34450705074701
BaseRepresentation
bin1100001001001100100000…
…0101011011111000100111
31202021110010212102020121220
43002103020011123320213
53222230112444132403
644221513235511423
72545441601541645
oct302231005337047
952243125366556
1013352115224103
114288666a56237
1215b7890458573
1375b139845226
14342362788195
151824bc25d953
hexc24c815be27

13352115224103 has 4 divisors (see below), whose sum is σ = 17802820298808. Its totient is φ = 8901410149400.

The previous prime is 13352115224101. The next prime is 13352115224111. The reversal of 13352115224103 is 30142251125331.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13352115224103 - 21 = 13352115224101 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13352115224101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2225352537348 + ... + 2225352537353.

It is an arithmetic number, because the mean of its divisors is an integer number (4450705074702).

Almost surely, 213352115224103 is an apocalyptic number.

13352115224103 is a deficient number, since it is larger than the sum of its proper divisors (4450705074705).

13352115224103 is an equidigital number, since it uses as much as digits as its factorization.

13352115224103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4450705074704.

The product of its (nonzero) digits is 21600, while the sum is 33.

Adding to 13352115224103 its reverse (30142251125331), we get a palindrome (43494366349434).

The spelling of 13352115224103 in words is "thirteen trillion, three hundred fifty-two billion, one hundred fifteen million, two hundred twenty-four thousand, one hundred three".

Divisors: 1 3 4450705074701 13352115224103