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13352412000 = 2535317293761
BaseRepresentation
bin11000110111101110…
…11010001101100000
31021110112220210211210
430123313122031200
5204321204141000
610044540310120
7651612425604
oct143367321540
937415823753
1013352412000
1157320a7844
122707842340
13134a3c0a05
149094a3504
15532365350
hex31bdda360

13352412000 has 768 divisors, whose sum is σ = 50014298880. Its totient is φ = 3096576000.

The previous prime is 13352411929. The next prime is 13352412091. The reversal of 13352412000 is 21425331.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 218891970 + ... + 218892030.

It is an arithmetic number, because the mean of its divisors is an integer number (65122785).

Almost surely, 213352412000 is an apocalyptic number.

13352412000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13352412000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (25007149440).

13352412000 is an abundant number, since it is smaller than the sum of its proper divisors (36661886880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13352412000 is a wasteful number, since it uses less digits than its factorization.

13352412000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 172 (or 154 counting only the distinct ones).

The product of its (nonzero) digits is 720, while the sum is 21.

Adding to 13352412000 its reverse (21425331), we get a palindrome (13373837331).

The spelling of 13352412000 in words is "thirteen billion, three hundred fifty-two million, four hundred twelve thousand".