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13352430503 = 53251932651
BaseRepresentation
bin11000110111101110…
…11110101110100111
31021110112221202020002
430123313132232213
5204321210234003
610044540531515
7651612533546
oct143367365647
937415852202
1013352430503
11573210a735
122707850b9b
13134a3c9269
149094aa15d
1553236aa88
hex31bddeba7

13352430503 has 4 divisors (see below), whose sum is σ = 13604363208. Its totient is φ = 13100497800.

The previous prime is 13352430499. The next prime is 13352430529. The reversal of 13352430503 is 30503425331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13352430503 - 22 = 13352430499 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13352430103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 125966273 + ... + 125966378.

It is an arithmetic number, because the mean of its divisors is an integer number (3401090802).

Almost surely, 213352430503 is an apocalyptic number.

13352430503 is a deficient number, since it is larger than the sum of its proper divisors (251932705).

13352430503 is an equidigital number, since it uses as much as digits as its factorization.

13352430503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 251932704.

The product of its (nonzero) digits is 16200, while the sum is 29.

Adding to 13352430503 its reverse (30503425331), we get a palindrome (43855855834).

The spelling of 13352430503 in words is "thirteen billion, three hundred fifty-two million, four hundred thirty thousand, five hundred three".

Divisors: 1 53 251932651 13352430503