13352525124401 has 4 divisors (see below), whose sum is σ = 13352641290852. Its totient is φ = 13352408957952.

The previous prime is 13352525124373. The next prime is 13352525124403. The reversal of 13352525124401 is 10442152525331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2390499423376 + 10962025701025 = 1546124^2 + 3310895^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13352525124401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13352525124403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57910640 + ... + 58140753.

It is an arithmetic number, because the mean of its divisors is an integer number (3338160322713).

Almost surely, 2^{13352525124401} is an apocalyptic number.

It is an amenable number.

13352525124401 is a deficient number, since it is larger than the sum of its proper divisors (116166451).

13352525124401 is a wasteful number, since it uses less digits than its factorization.

13352525124401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 116166450.

The product of its (nonzero) digits is 144000, while the sum is 38.

Adding to 13352525124401 its reverse (10442152525331), we get a palindrome (23794677649732).

The spelling of 13352525124401 in words is "thirteen trillion, three hundred fifty-two billion, five hundred twenty-five million, one hundred twenty-four thousand, four hundred one".