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13352525124373 is a prime number
BaseRepresentation
bin1100001001001110000010…
…0001000101001100010101
31202021111012102201100002101
43002103200201011030111
53222231432412434443
644222022041242101
72545455006616321
oct302234041051425
952244172640071
1013352525124373
114288857373396
1215b7985793331
1375b1a3741b76
143423a0da8981
151824e322a84d
hexc24e0845315

13352525124373 has 2 divisors, whose sum is σ = 13352525124374. Its totient is φ = 13352525124372.

The previous prime is 13352525124359. The next prime is 13352525124403. The reversal of 13352525124373 is 37342152525331.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12411824933764 + 940700190609 = 3523042^2 + 969897^2 .

It is an emirp because it is prime and its reverse (37342152525331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13352525124373 - 225 = 13352491569941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13352525127373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676262562186 + 6676262562187.

It is an arithmetic number, because the mean of its divisors is an integer number (6676262562187).

Almost surely, 213352525124373 is an apocalyptic number.

It is an amenable number.

13352525124373 is a deficient number, since it is larger than the sum of its proper divisors (1).

13352525124373 is an equidigital number, since it uses as much as digits as its factorization.

13352525124373 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2268000, while the sum is 46.

The spelling of 13352525124373 in words is "thirteen trillion, three hundred fifty-two billion, five hundred twenty-five million, one hundred twenty-four thousand, three hundred seventy-three".