Base | Representation |
---|---|
bin | 11110010111001000101000… |
… | …101111000011010000000011 |
3 | 122111210110102002010200020022 |
4 | 132113020220233003100003 |
5 | 120000233412430432423 |
6 | 1151555221042004055 |
7 | 40061212013061242 |
oct | 3627105057032003 |
9 | 574713362120208 |
10 | 133531216655363 |
11 | 396022a871762a |
12 | 12b872b234662b |
13 | 5967c2a6a1357 |
14 | 24d8d3414a959 |
15 | 10686c0274dc8 |
hex | 797228bc3403 |
133531216655363 has 4 divisors (see below), whose sum is σ = 134027615230560. Its totient is φ = 133034818080168.
The previous prime is 133531216655359. The next prime is 133531216655377. The reversal of 133531216655363 is 363556612135331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 133531216655363 - 22 = 133531216655359 is a prime.
It is a super-2 number, since 2×1335312166553632 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133531216658363) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 248199287195 + ... + 248199287732.
It is an arithmetic number, because the mean of its divisors is an integer number (33506903807640).
Almost surely, 2133531216655363 is an apocalyptic number.
133531216655363 is a deficient number, since it is larger than the sum of its proper divisors (496398575197).
133531216655363 is an equidigital number, since it uses as much as digits as its factorization.
133531216655363 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 496398575196.
The product of its digits is 13122000, while the sum is 53.
The spelling of 133531216655363 in words is "one hundred thirty-three trillion, five hundred thirty-one billion, two hundred sixteen million, six hundred fifty-five thousand, three hundred sixty-three".
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