Base | Representation |
---|---|
bin | 111110001011100100… |
… | …0010100101100000101 |
3 | 110202200002002200011122 |
4 | 1330113020110230011 |
5 | 4141433200402122 |
6 | 141202131043325 |
7 | 12435022434560 |
oct | 1742710245405 |
9 | 422602080148 |
10 | 133532044037 |
11 | 516a33a3097 |
12 | 21a67740545 |
13 | c790880612 |
14 | 666a6094d7 |
15 | 3717ea0142 |
hex | 1f17214b05 |
133532044037 has 16 divisors (see below), whose sum is σ = 155984348160. Its totient is φ = 111937617792.
The previous prime is 133532044033. The next prime is 133532044049. The reversal of 133532044037 is 730440235331.
It is not a de Polignac number, because 133532044037 - 22 = 133532044033 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 133532043988 and 133532044006.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133532044033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 458837 + ... + 691082.
It is an arithmetic number, because the mean of its divisors is an integer number (9749021760).
Almost surely, 2133532044037 is an apocalyptic number.
It is an amenable number.
133532044037 is a deficient number, since it is larger than the sum of its proper divisors (22452304123).
133532044037 is a wasteful number, since it uses less digits than its factorization.
133532044037 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1150292.
The product of its (nonzero) digits is 90720, while the sum is 35.
Adding to 133532044037 its reverse (730440235331), we get a palindrome (863972279368).
The spelling of 133532044037 in words is "one hundred thirty-three billion, five hundred thirty-two million, forty-four thousand, thirty-seven".
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