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133533050031119 = 1044399712785627
BaseRepresentation
bin11110010111001010010110…
…000000110100110000001111
3122111210122010211221210222002
4132113022112000310300033
5120000301141301443434
61152000123013342515
740061305314364124
oct3627122600646017
9574718124853862
10133533050031119
11396030595a7a02
1212b87724337a3b
135968160478a8b
1424d906983074b
15106877b1c257e
hex797296034c0f

133533050031119 has 4 divisors (see below), whose sum is σ = 133533073260744. Its totient is φ = 133533026801496.

The previous prime is 133533050031089. The next prime is 133533050031131. The reversal of 133533050031119 is 911130050335331.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133533050031119 is a prime.

It is a super-2 number, since 2×1335330500311192 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133533050030119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4051184 + ... + 16836810.

It is an arithmetic number, because the mean of its divisors is an integer number (33383268315186).

Almost surely, 2133533050031119 is an apocalyptic number.

133533050031119 is a deficient number, since it is larger than the sum of its proper divisors (23229625).

133533050031119 is a wasteful number, since it uses less digits than its factorization.

133533050031119 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23229624.

The product of its (nonzero) digits is 54675, while the sum is 38.

The spelling of 133533050031119 in words is "one hundred thirty-three trillion, five hundred thirty-three billion, fifty million, thirty-one thousand, one hundred nineteen".

Divisors: 1 10443997 12785627 133533050031119